3b^2-3q^2=

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Solution for 3b^2-3q^2= equation: 


Simplifying
3b2 + -3q2 = 0

Solving
3b2 + -3q2 = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '3q2' to each side of the equation.
3b2 + -3q2 + 3q2 = 0 + 3q2

Combine like terms: -3q2 + 3q2 = 0
3b2 + 0 = 0 + 3q2
3b2 = 0 + 3q2
Remove the zero:
3b2 = 3q2

Divide each side by '3'.
b2 = q2

Simplifying
b2 = q2

Take the square root of each side:
b = {-1q, q}

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